Inclination angle between the orbital plane and the plane of the sky

AI Thread Summary
The discussion focuses on calculating the indirect inclination angle of an orbital plane given a direct inclination angle of 40 degrees. The proposed solution suggests that the indirect angle can be found using the formula 180 - 40, resulting in an indirect angle of 140 degrees. Participants emphasize the importance of understanding the definitions of direct and indirect angles in celestial mechanics. Additional context about the specific celestial bodies or scenarios involved is requested for clarity. The calculation appears correct based on the definitions provided.
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Homework Statement



I have the inclinination i which is the angle between the orbital plane and the plane of the sky, i [0,pi/2] if it is in the direct sense ans [pi/2, pi] in the indirect, so here i have an angle i=40 in the direct sense how can i calculate the i in the indirect sense

Homework Equations

The Attempt at a Solution


i don't know maybe 180-40=140
 
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If I am interpreting your context correctly, you're asking about orbital inclinations in the context of celestial bodies. If you defined the direct and indirect angles to be as such, then yes it seems that it is a matter of 180-40. Do give us a bit more context though, it will be helpful :)
 
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