How Does Accelerating on an Incline Affect G-Force?

[IMK]

Hello,
I am in a car and accelerating on the horizontal at a rate of say 1mss I wound be subjected to 0.1g acceleration on my back, correct?

However if I accelerate in the same car at the same 1mss up and incline of 45 degrees what would be the g force on my back please? And how do I calculate it , is it the sine of the angle of incline of gravity + my the 1mss driving acceleration.

Many thanks IMK

 

[Hootenanny]

I am in a car and accelerating on the horizontal at a rate of say 1mss I wound be subjected to 0.1g acceleration on my back, correct?

Assuming g = 10 m.s^-2, yes.

However if I accelerate in the same car at the same 1mss up and incline of 45 degrees what would be the g force on my back please? And how do I calculate it , is it the sine of the angle of incline of gravity + my the 1mss driving acceleration.

You would draw yourself a free body diagram and examine the forces acting, resolving them parallel to the slope. And yes, you would find that the force exerted at your back would be the sum of your [combined] weight, resolved parallel to the incline and the force due to the 0.1g acceleration. Note it is always best in this case to work with forces first and then resolve into an acceleration.

 

[Moetasim]

Hello IMK,

I can provide you with a response to your question. Incline acceleration force refers to the force experienced by an object when it is accelerating on an inclined surface. In your scenario, when you are accelerating on a horizontal surface, you would experience a force on your back equivalent to 0.1g, where g is the acceleration due to gravity (9.8m/s^2).

However, when you accelerate on an incline of 45 degrees, the force on your back would be different. To calculate this force, we need to consider the components of the acceleration. The 1m/s^2 acceleration you mentioned is the horizontal component, while the vertical component would be 1m/s^2 multiplied by the sine of the angle of incline (45 degrees). This vertical component would contribute to the force on your back.

To calculate the total force on your back, we can use the Pythagorean theorem, which states that the square of the hypotenuse (the total force) is equal to the sum of the squares of the other two sides (the horizontal and vertical components). So, the total force on your back would be the square root of (0.1g)^2 + (1m/s^2 * sin 45 degrees)^2 = 0.101g.

Therefore, when accelerating on an incline of 45 degrees, you would experience a force on your back equivalent to 0.101g, slightly higher than the force experienced on a horizontal surface. I hope this helps to clarify your question. If you have any further inquiries, please feel free to ask. Thank you.