A box is pulled up an incline which is 285 m long and in the process the box rises 16.7 m. The force pulling the truck is 18300 N.
A) If there was no friction, what is the weight and mass of the box? B)If friction provides a force of 17,400 N, what is the force pulling the box?
c) What is the IMA?
The Attempt at a Solution
A)The weight would just be 18300 N I believe, since it is the effort force. and w=mg, so 18300=m(9.81), so m=1865.4 g?
B) 18300-17400=900 N force pulling box
C) IMA=De/Dr To find the effort distance,would you square 16.7+square 285?
Im really confused on inclined planes, so any tips on what Im doing wrong would be great :)