Incoming spacelike radial geodesic

  • Thread starter Thread starter deadringer
  • Start date Start date
  • Tags Tags
    Geodesic Radial
deadringer
Messages
32
Reaction score
0
We need to show that using the Schwarzschild metric, an incoming radial spacelike geodesic satisfies r>= 1m/(1 + E^2)

I know that E = (1-2m/r) is constant, and I think that ds squared should be negative for a spacelike geodesic. I try substituting E into the metric and setting ds squared <=0 but this does not give the required expressions. I'm also unsure about the meaning of "incoming" - does this mean dr/ds or dr/dt < 0?
 
Physics news on Phys.org
This is not making sense to me on so many levels. If E = (1-2m/r) is a constant then r is a constant. And that's hardly 'incoming'. What are the geodesic equations in the Schwarzschild metric with constant angular coordinates?
 
Sorry I meant to say that E = (1-2m/r) dt/ds is constant (this is one geodesic equation).
 
The other geodesic equation gives us d^2 s/dt^2 which I don't think is useful.
 
Ah, ok. Finally straightened out. And the '1' in the numerator of the radius inequality is supposed to be a '2'. I think your main problem is trying to set ds^2 to be negative in some vague way. Spacelike or timelike is determined by the sign of g*t*t - where g is the metric tensor and t is a tangent vector. Further, in the case of a nonnull geodesic you can set this quantity equal to plus or minus one (defining proper time). Which that is depends on whether the geodesic is timelike or spacelike (and your metric convention).
 
Thanks very much Dick. It's all clear now.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top