- #1

MathewsMD

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I have a 2D Gaussian:

## f(x,y) = e^{-[(x-x_o)^2 + (y-y_o)^2]/(2*{sigma}^2)}##

which I converted into polar coordinates and got:

## g(r,θ) = e^{-[r^2 + r_o^2 - 2*r*r_o(cos(θ)cos(θ_o) + sin(θ)sin(θ_o))]/({2*{sigma}^2})} ##

The proof for how this was done is in the attached file, and it would be great if someone could verify my steps in case I messed up somewhere (although I have inputted values and it seems to work). I have plotted the functions, and they do seem comparable by visual inspection, too.

The characteristics of the functions (including ## sigma_o##) are manually specified by me, so the values for ##x_o##, ##y_o## match up with ##r_o## and ##θ_o##. Now, when I integrate these functions over the same regions, I don't always get the same answers. For example, when ##r = 0## or ##θ = 0##, I do get the same answers, but when ##θ \neq 0##, then the answers are slightly off. I have been trying to search for where I'm going wrong, and it may be completely obvious (likely associated with the sine and cosine terms), but I'm just not seeing it. The fact that the values from completing the integration on Python (in polar coordinates) and WolframAlpha (in cartesian coordinates) are relatively similar for the cases where ##θ \neq 0## seems a little odd to me. If anyone has any thoughts, it would be greatly appreciated!

Here is my code:

I've also been trying points in both f and g to see if they correspond, and they seem to work. For example, if:

##sigma = 1##

##x_o = 1##

##y_o = 2##

then ## f(1,1) = e^{-0.5} ##

This also corresponds to:

##r_o = \sqrt{26} ##

##θ_o = ~1.107##

then ##g(\sqrt{2},pi/4) = e^{-0.5}##

I am leaning towards there being an error in my actual integration, but do you see any?

If I use these values for the code:

##sigma0 = 5##

##r0 = 2**0.5##

##theta0 = 1.75*np.pi##

Then the value for the integral I get is: 1.33556147e+01

When I do this in WolframAlpha, I get: 12.7035

Any advice is welcome!

## f(x,y) = e^{-[(x-x_o)^2 + (y-y_o)^2]/(2*{sigma}^2)}##

which I converted into polar coordinates and got:

## g(r,θ) = e^{-[r^2 + r_o^2 - 2*r*r_o(cos(θ)cos(θ_o) + sin(θ)sin(θ_o))]/({2*{sigma}^2})} ##

The proof for how this was done is in the attached file, and it would be great if someone could verify my steps in case I messed up somewhere (although I have inputted values and it seems to work). I have plotted the functions, and they do seem comparable by visual inspection, too.

The characteristics of the functions (including ## sigma_o##) are manually specified by me, so the values for ##x_o##, ##y_o## match up with ##r_o## and ##θ_o##. Now, when I integrate these functions over the same regions, I don't always get the same answers. For example, when ##r = 0## or ##θ = 0##, I do get the same answers, but when ##θ \neq 0##, then the answers are slightly off. I have been trying to search for where I'm going wrong, and it may be completely obvious (likely associated with the sine and cosine terms), but I'm just not seeing it. The fact that the values from completing the integration on Python (in polar coordinates) and WolframAlpha (in cartesian coordinates) are relatively similar for the cases where ##θ \neq 0## seems a little odd to me. If anyone has any thoughts, it would be greatly appreciated!

Here is my code:

Code:

```
import numpy as np
from scipy import integrate
RIT = [] # Region Intensity (integration)
i = 0
N = 1
while i < N: #1 random beam generated
i = i + 1
sigma0 = 5 # just an example--arbitrary, I usually set it between 1 and 10
r0 = #you can input any value here, I usually set it between 0 and 10
theta0 = random.uniform(0,np.pi*2) #you can make it arbitrary instead of random if you wish
def G(r,theta): #this is the Gaussian in polar coordinates
return (np.e**(-((r**2 + r0**2 \
- 2*r*r0*(np.cos(theta)*np.cos(theta0) + \
np.sin(theta)*np.sin(theta0)))/(2*sigma0**2))))*r
#this r is here because
#the integrand includes dr and dtheta, NOT dx and dy any longer!
RI = integrate.nquad(G, [[4,7],[0,0.5*np.pi]]) #this region is between r = 4 and 7 in the first quadrant
RIT.append(RI)
print RIT
```

I've also been trying points in both f and g to see if they correspond, and they seem to work. For example, if:

##sigma = 1##

##x_o = 1##

##y_o = 2##

then ## f(1,1) = e^{-0.5} ##

This also corresponds to:

##r_o = \sqrt{26} ##

##θ_o = ~1.107##

then ##g(\sqrt{2},pi/4) = e^{-0.5}##

I am leaning towards there being an error in my actual integration, but do you see any?

If I use these values for the code:

##sigma0 = 5##

##r0 = 2**0.5##

##theta0 = 1.75*np.pi##

Then the value for the integral I get is: 1.33556147e+01

When I do this in WolframAlpha, I get: 12.7035

Any advice is welcome!

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