Increase Catalyst Surface Area & Reaction Rate: Experiment

AI Thread Summary
Increasing the mass of MnO2 as a catalyst in H2O2 decomposition leads to a measurable increase in temperature change, indicating a higher reaction rate. The relationship between catalyst surface area and reaction rate suggests that more surface area allows for more active sites for the reaction to occur. While the trend shows that adding more MnO2 generally increases the reaction rate, the assumptions of uniform particle dispersion and constant rate over time may not hold true in all cases. The discussion highlights the importance of understanding how surface area impacts catalytic efficiency, particularly in industrial applications. Overall, the experiment supports the theory that reaction rate is proportional to the surface area of the catalyst used.
tvbuddy01
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Hi there,

I am doing an experiment in increasing the mass of MnO2 when it is added to H2O2 decomposition, and I'm measuring the rate of temperature change. I chose increments of 0.050, 0.100, 0.150, 0.200, and 0.250 g to put into H2O2 when it is decomposed, i.e. the MnO2 is a catalyst. I noticed a generally increasing trend.

I was wondering... I know that increasing the mass of the catalyst is just increasing the total surface area it has, but how exactly is surface area related to the rate of reaction?
 
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Ideally rate should be simply proportional to surface area which then should be proportional to the mass added if it is a uniform dispersed solution of particles. I.e. Particles not clumping together or sticking to the glass. Those assumptions may not be the case in your experiment. Also are you really measuring a rate? Does it seem to be constant with time in your experiment?
 
I do have an increasing trend. i.e. the more MnO2 I added in, the higher the rate.

Why exactly is the rate proportional to surface area of the catalyst?
 
Things like it are actually called 'surface catalysts' (and include I'd say, the majority of large scale industrial reactions).
In a very generic way guess how they work. Isn't proportionality to area what you'd expect?
 
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