Incredibly basic Coulomb's law question - am I being silly?

  • Thread starter Thread starter smileandbehappy
  • Start date Start date
  • Tags Tags
    Coulomb's law Law
Click For Summary

Homework Help Overview

The discussion revolves around a problem related to Coulomb's law, specifically focusing on the forces acting on a charge due to other charges. Participants are examining the components of these forces and questioning the presence of a y-component in the resultant force.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are exploring the y-components of forces acting on a charge and questioning whether they cancel each other out. There is discussion about using the parallelogram method for vector addition and the importance of considering the magnitudes of the charges involved.

Discussion Status

Some participants have provided guidance on the necessity of accounting for charge magnitudes when determining the resultant force. There is an acknowledgment of the original poster's confusion regarding the y-component of the forces, and a suggestion to clarify the diagram used in the problem.

Contextual Notes

There are mentions of constraints such as the original poster's time limitations due to exam preparation and the forum's rules regarding posting formats, which may affect the clarity of the discussion.

smileandbehappy
Messages
66
Reaction score
0
member reminded that problem statement should be text and not a graphic
I've attached my workings... But is this correct? I can't see the fault with it. However I can't see how there will be no y-component to the force... Can someone a bit smarter than me tell me if I'm being really dim.

17387568979_224c324095_b.jpg
https://flic.kr/p/sutQu4][/PLAIN]
 
Last edited by a moderator:
Physics news on Phys.org
smileandbehappy said:
However I can't see how there will be no y-component to the force...
What's the y-component of the force from B on C? Compare that to the y-component of the force from A on C.

(I'm having trouble reading your diagram.)
 
Doc Al said:
What's the y-component of the force from B on C? Compare that to the y-component of the force from A on C.

(I'm having trouble reading your diagram.)

Apologies about the poor iphone photo/my diagram drawing skills. If you click on the link you can then zoom in and see it better. I am no good at typing things out - and it seems like a waste of time to do so to ask a question, so I just photo my work. But I do realize it's a pain.

I have done this and found that the y-component for Fca and Fcb cancel each other out. Which is what I have a problem with. I have tried to draw out the what the ovreral force should look like... However I think I should get a y-component from the overall force... Noting here I am just using the paralellogram method and am not taking into account the magnitude of the charges...

Hold on - are you saying I should look at the relative sizes of the charges and compare them to the y component using the angle... If so I've seen this done before however I have never done it myself. I always just use the algebra and maths to give me an answer. I usually get the right answer to drop out - however sadly you are always a little unsure if you have it right or not.
 
smileandbehappy said:
I have done this and found that the y-component for Fca and Fcb cancel each other out.
Right.

smileandbehappy said:
Which is what I have a problem with.

smileandbehappy said:
I have tried to draw out the what the ovreral force should look like... However I think I should get a y-component from the overall force... Noting here I am just using the paralellogram method and am not taking into account the magnitude of the charges...
If you used the parallelogram method properly to add those vectors, you would get a net force on C that would have no y-component. You must take into account the magnitude of the charges as they determine the magnitude of the forces!

smileandbehappy said:
Hold on - are you saying I should look at the relative sizes of the charges and compare them to the y component using the angle...
You certainly must consider the relative charges to properly scale your forces when drawing your parallelogram.
 
  • Like
Likes   Reactions: smileandbehappy
Doc Al said:
Right.

If you used the parallelogram method properly to add those vectors, you would get a net force on C that would have no y-component. You must take into account the magnitude of the charges as they determine the magnitude of the forces!

You certainly must consider the relative charges to properly scale your forces when drawing your parallelogram.

Thanks - I will do that in the future. I am currently revising for an exam where I only have around 5 minutes so answer both parts of that question including reading and checking time - so I can't do too much. But i do appreciate if I am going to do something I should do it properly.

For the avoidance of doubt - and because I'm a bit dim. Is the answer correct? Thanks Sam
 
smileandbehappy said:
I am no good at typing things out - and it seems like a waste of time to do so to ask a question, so I just photo my work.
Posting your problem as an image and not following the homework template is against our rules. (See: How to Ask for Homework Help)

(My bad for not pointing this out sooner.)

smileandbehappy said:
Thanks - I will do that in the future. I am currently revising for an exam where I only have around 5 minutes so answer both parts of that question including reading and checking time - so I can't do too much.
On an exam, I would not waste time with graphical addition of vectors.

smileandbehappy said:
For the avoidance of doubt - and because I'm a bit dim. Is the answer correct?
Type out your answer and I'll check it out.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
17K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 5 ·
Replies
5
Views
922
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 12 ·
Replies
12
Views
6K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K