Indefinite Integral Calculus II

  • Thread starter Wm_Davies
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  • #1
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Homework Statement



[tex]\int \frac{ \tan x \sec^2 x }{ \tan^2 x + 6 \tan x + 8 } dx[/tex]

Homework Equations





The Attempt at a Solution



[tex]\int \frac{ \tan x \sec^2 x }{ \tan^2 x + 6 \tan x + 8 } dx[/tex]
Okay I let....

[tex]u=tanx[/tex]
[tex]du=sec^2x[/tex]


Then I got

[tex]\int \frac{ u }{ (u+4)(u+2) } du[/tex]

Then I split this into partial fractions which is not working...... for some reason. Can somebody please help me?
 

Answers and Replies

  • #2
LCKurtz
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[tex]\frac {2}{u+4} + \frac{-1}{u+2}[/tex]
 

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