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Indefinite Integral Calculus II

  1. Feb 26, 2010 #1
    1. The problem statement, all variables and given/known data

    [tex]\int \frac{ \tan x \sec^2 x }{ \tan^2 x + 6 \tan x + 8 } dx[/tex]

    2. Relevant equations

    3. The attempt at a solution

    [tex]\int \frac{ \tan x \sec^2 x }{ \tan^2 x + 6 \tan x + 8 } dx[/tex]
    Okay I let....


    Then I got

    [tex]\int \frac{ u }{ (u+4)(u+2) } du[/tex]

    Then I split this into partial fractions which is not working...... for some reason. Can somebody please help me?
  2. jcsd
  3. Feb 26, 2010 #2


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    [tex]\frac {2}{u+4} + \frac{-1}{u+2}[/tex]
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