Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Indefinte integrals

  1. Apr 14, 2014 #1
    [tex]\int \frac{d}{dx}f(x)dx = f(x) + C_x[/tex] [tex]\iint \frac{d^2}{dx^2}f(x)dx^2 = f(x) + xC_x + C_{xx}[/tex]
    [tex]\int \frac{\partial}{\partial x}f(x,y)dx = f(x,y) + g_x(y)[/tex] [tex]\int \frac{\partial}{\partial y}f(x,y)dy = f(x,y) + g_y(x)[/tex]
    [tex]\iint \frac{\partial^2}{\partial x^2}f(x,y)dx^2 = f(x,y) + x g_{x}(y) + g_{xx}(y)[/tex] [tex]\iint \frac{\partial^2}{\partial x \partial y}f(x,y)dxdy = f(x,y) + \int_{y_0}^{y}g_x(y)dy + G_x(y_0) + g_y(x)[/tex] [tex]\iint \frac{\partial^2}{\partial y \partial x}f(x,y)dydx = f(x,y) + \int_{x_0}^{x}g_y(x)dx + G_y(x_0) + g_x(y)[/tex] [tex]\iint \frac{\partial^2}{\partial y^2}f(x,y)dy^2 = f(x,y) + y g_y(x) + g_{yy}(x)[/tex]

    I was trying apply the idea of indefinite integral (ie, the antiderivative of a function + a arbitrary constant/function) for all possible cases. You think that all equation above are correct?
  2. jcsd
  3. Apr 15, 2014 #2


    User Avatar
    Science Advisor

    I would NOT write "[itex]dx^2[/itex]" for a double integral. And, frankly, I can see no point in writing out all those integrals!
  4. Apr 15, 2014 #3
    IMO, those integral are usefull for didactic efect.
  5. Apr 15, 2014 #4


    Staff: Mentor

    +1 to both.

    For what purpose - to be memorized?
  6. Apr 15, 2014 #5
    In my mathematical career, I have never needed integral tables like in the OP.
  7. Apr 15, 2014 #6
    Anyway, you want to know whether the formulas are correct? Well, then give us a proof of the formula and we'll tell you if the proof is right or wrong.
  8. Apr 15, 2014 #7
    How you express a family of antiderivative of a function (f'(x)) that haven't integral?

    ##\int f'(x) dx = \int_{x_0}^{x} f'(x) dx + f(x_0) + C##

    But if you want to integrate twice a function (f''(x) (in this case)) that haven't integral in terms of elementary functions? Answer:

    ##\iint f''(x) dxdx = \iint_{x_0 x_0}^{x\;x} f''(x) dx dx + f'(x_0)(x - x_0) + f(x_0) + xC_1 + C_2##

    Why Riemann did want to study and develop his theory of differential geometry if hadn't application? Why he wanted. Sometimes a theory haven't practice application but has just theoretical application.
  9. Apr 15, 2014 #8


    Staff: Mentor

    What good does having this formula do for you? If f'' doesn't have an antiderivative in terms of elementary functions, then how are you going to get f', or for that matter, f?
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook