Indeoendent current source in series with a resistor

  • #1
Guys, this seems very trivial yet I can not come to the correct answer and I've searched everywhere.

I am asked to find the node voltages using nodal analysis. The trouble is I don't know how to express a current in a brach between 2 unknown voltages where there is an independent current source in series with a resistor.

I think it should be

(V1-V2)/R +I ; for that specific branch, where I is the independent current source in that branch.

Can somebody verify that? Please
 

Answers and Replies

  • #2
2,051
317
Guys, this seems very trivial yet I can not come to the correct answer and I've searched everywhere.

I am asked to find the node voltages using nodal analysis. The trouble is I don't know how to express a current in a brach between 2 unknown voltages where there is an independent current source in series with a resistor.

I think it should be

(V1-V2)/R +I ; for that specific branch, where I is the independent current source in that branch.

Can somebody verify that? Please

The current through the current source is always I. That's why it's a current source. The current through anything in series with it is also always I.
 

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