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Indeoendent current source in series with a resistor

  1. Sep 18, 2014 #1
    Guys, this seems very trivial yet I can not come to the correct answer and I've searched everywhere.

    I am asked to find the node voltages using nodal analysis. The trouble is I don't know how to express a current in a brach between 2 unknown voltages where there is an independent current source in series with a resistor.

    I think it should be

    (V1-V2)/R +I ; for that specific branch, where I is the independent current source in that branch.

    Can somebody verify that? Please
  2. jcsd
  3. Sep 19, 2014 #2
    The current through the current source is always I. That's why it's a current source. The current through anything in series with it is also always I.
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