Indeoendent current source in series with a resistor

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 2K views
EEngineeruic
Messages
1
Reaction score
0
Guys, this seems very trivial yet I can not come to the correct answer and I've searched everywhere.

I am asked to find the node voltages using nodal analysis. The trouble is I don't know how to express a current in a brach between 2 unknown voltages where there is an independent current source in series with a resistor.

I think it should be

(V1-V2)/R +I ; for that specific branch, where I is the independent current source in that branch.

Can somebody verify that? Please
 
Physics news on Phys.org
EEngineeruic said:
Guys, this seems very trivial yet I can not come to the correct answer and I've searched everywhere.

I am asked to find the node voltages using nodal analysis. The trouble is I don't know how to express a current in a brach between 2 unknown voltages where there is an independent current source in series with a resistor.

I think it should be

(V1-V2)/R +I ; for that specific branch, where I is the independent current source in that branch.

Can somebody verify that? Please

The current through the current source is always I. That's why it's a current source. The current through anything in series with it is also always I.