Indeoendent current source in series with a resistor

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SUMMARY

The discussion focuses on using nodal analysis to find node voltages in a circuit containing an independent current source in series with a resistor. The correct expression for the current in a branch between two unknown voltages, V1 and V2, is confirmed to be (V1-V2)/R + I, where I represents the independent current source. Participants emphasize that the current through the current source remains constant at I, and this current also flows through the series resistor.

PREREQUISITES
  • Nodal analysis in electrical circuits
  • Understanding of independent current sources
  • Basic circuit theory involving resistors
  • Voltage and current relationships in series circuits
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Electrical engineering students, circuit designers, and anyone involved in analyzing and designing electrical circuits using nodal analysis.

EEngineeruic
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Guys, this seems very trivial yet I can not come to the correct answer and I've searched everywhere.

I am asked to find the node voltages using nodal analysis. The trouble is I don't know how to express a current in a brach between 2 unknown voltages where there is an independent current source in series with a resistor.

I think it should be

(V1-V2)/R +I ; for that specific branch, where I is the independent current source in that branch.

Can somebody verify that? Please
 
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EEngineeruic said:
Guys, this seems very trivial yet I can not come to the correct answer and I've searched everywhere.

I am asked to find the node voltages using nodal analysis. The trouble is I don't know how to express a current in a brach between 2 unknown voltages where there is an independent current source in series with a resistor.

I think it should be

(V1-V2)/R +I ; for that specific branch, where I is the independent current source in that branch.

Can somebody verify that? Please

The current through the current source is always I. That's why it's a current source. The current through anything in series with it is also always I.
 

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