Independent current and voltage network analysis

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Discussion Overview

The discussion revolves around analyzing a circuit with two current sources and three voltage sources, specifically focusing on calculating the power supplied by each current source. The context includes homework-related problem-solving using Kirchhoff's laws.

Discussion Character

  • Homework-related
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant states that the textbook indicates the 2mA current source supplies 6mW and the 1mA current source supplies -7mW.
  • Another participant attempts to explain their reasoning by suggesting that they subtract the voltages (5V from 8V and 15V from 8V) and multiply by the respective current sources to arrive at the power values.
  • A participant expresses uncertainty about the signs of the power values, proposing they might be -6mW and +7mW instead.
  • Another participant asserts that the +8V source establishes a voltage of 8V between the far left and far right nodes, emphasizing the certainty of this point.
  • One participant suggests a method for approaching circuit problems by assigning a reference node and evaluating voltages across branches, noting the importance of sign conventions in power calculations.

Areas of Agreement / Disagreement

Participants express differing views on the signs of the power calculations, with some uncertainty about the correct values. There is no consensus on the final answers or the reasoning behind them.

Contextual Notes

Participants reference Kirchhoff's laws and voltage relationships, but there are unresolved assumptions regarding the circuit configuration and the application of these laws in their calculations.

qizzlestick
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Homework Statement


there's two current sources and three voltages sources the problem wants to know the power supplied by each current source


Homework Equations


according to the book the problem can be solved using Kirchoffs current law and kirchhoffs voltage law

The answers according to the textbook the 2mA current source supplies 6mW and the 1 mA current source supplies -7mW

The Attempt at a Solution


I can only guess that they subtract the 5v by the 8v then multiply the result by the 2mA.
Also subtract the 15v by the 8v and multiply the result by the 1mA source to get the -7mW answer.
 

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qizzlestick said:

The Attempt at a Solution


I can only guess that they subtract the 5v by the 8v then multiply the result by the 2mA.
Also subtract the 15v by the 8v and multiply the result by the 1mA source to get the -7mW answer.
This is correct, but can you explain why? (I'm not sure about the signs though. I think they should be -6 mW and +7 mW, but I could be wrong.)
 
The +8v source sets the voltage between the far left and far right nodes to be 8v, with the left node positive. No IF's or BUT's about it.
 
Best way to approach such ckt problems is to assume a reference node and assign a zero potential to it.Next move across the branches and assign voltages to other nodes by appropriately adding or subtracting voltages keeping in mind you assign movin from lower potential to higher potential a PLUS sign. Then you would have got voltages at all nodes then evaluate power using V*I . Power is being supplied or is positive if current is flowin from higher potential to lower potential and dissipated if vice versa.

Hope its clear now
 
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