Independent events in statistics

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SUMMARY

The discussion focuses on proving the independence of two events in probability: drawing an ace as the first card (event A) and drawing an ace as the second card (event B) from a standard deck of cards with replacement. The probabilities are calculated as P(A) = 4/52 and P(B) = 4/52. The solution confirms that P(A and B) = P(A) * P(B) = (4/52) * (4/52), and since the cards are replaced, P(B|A) equals P(B), establishing that events A and B are independent.

PREREQUISITES
  • Understanding of basic probability concepts
  • Familiarity with independent events in statistics
  • Knowledge of conditional probability
  • Ability to calculate probabilities from a standard deck of cards
NEXT STEPS
  • Study the concept of independent events in probability theory
  • Learn about conditional probability and its applications
  • Explore the law of total probability
  • Practice problems involving drawing cards from a deck with and without replacement
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Students studying statistics, educators teaching probability concepts, and anyone interested in understanding the principles of independent events in probability theory.

stevecallaway
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Homework Statement


Two cards are drawn from a standard deck with replacement. A=first card is an ace. B=second card is an ace. Show that A and B are independent


Homework Equations


P(A and B)=P(A given B)/P(B)
P(A given B)=P(A)

The Attempt at a Solution


P(A)=4/52
P(B) =4/52
P(A and B)=[(4/52)(4/52)]/(4/52)=(4/52)=P(A)
So the question I'm having is how to find P(A and B)?
Am I correct that P(A and B)=(4/52)(4/52)?
 
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Is your definition of independence that P(B|A) = P(B)? You have already calculated P(B) = 4/52 = 1/13.

Now, given that A has happened, and the card has been replaced, what is P(B) then? That would give you P(B|A). If it is the same as P(B), you are done.
 

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