Independent solutions of scalar wave equations

AI Thread Summary
The scalar wave equation is a second-order partial differential equation, which typically has infinitely many independent solutions rather than just two. When solving it in spherical coordinates using separation of variables, the result is an infinite series involving Legendre polynomials, Bessel functions, and trigonometric functions. This complexity arises because the wave equation can be viewed as a set of coupled ordinary differential equations for each spatial point. A suggestion was made to apply d'Alembert's solution in three dimensions for a more straightforward approach. The discussion highlights the distinction between the expected two solutions for ordinary differential equations and the infinite solutions present in partial differential equations like the wave equation.
Karthiksrao
Messages
66
Reaction score
0
Hi,

This has been bothering me for a while now.. The scalar wave equation is a 2nd order differential equation. So we would expect two independent solutions for it.

However when you try to find the solution of the scalar wave equation (in spherical coordinates) by employing the separation of variables we would end up getting a series summation to infinite terms of (legendre polynomials)*(bessels)*(Trigonometric ) functions.

How do you find the *two* independent solutions from this infinite summation series ?

Thanks
 
Physics news on Phys.org
I guess you are trying this in three dimensions from the coordinate system, I can't figure out why you are not trying it in cartesian coordinates though.

Split it up and use d'Alembert's solution in all three dimensions to get a nicer answer?
 
I am looking at the 3D scalar wave equation in spherical coordinates which is a well discussed problem in electromagnetic theory. But thanks.
 
Second-order linear ordinary differential equations (ODEs) have two linearly independent solutions. The wave equation is a second order partial differential equation (PDE) and will have infinitely many independent solutions (e.g. u(x,y,z,t) = cos(k(x-ct)) is a solution for any real k). If you like you can think of the wave equation as an infinite number of coupled ODEs, one for each point in space.
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...

Similar threads

Back
Top