Index of when refraction/optics question

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To determine the index of refraction of the plastic placed over a focused black dot in a microscope, the problem involves applying Snell's law, specifically the equation n1*sin(theta1)=n2*sin(theta2). The microscope objective's adjustment of 0.380 cm indicates a change in apparent depth due to refraction. Participants suggest using geometric triangles to find the necessary angles, although there are more unknowns than equations. The concept of real versus apparent depth is also highlighted, as it relates to how objects appear under different mediums. Starting with a diagram is recommended to visualize the problem effectively.
Gino97
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The question
A microscope is focused on a black dot. When a 1.20 cm -thick piece of plastic is placed over the dot, the microscope objective has to be raised 0.380 cm to bring the dot back into focus.

What is the index of refraction of the plastic

Relevant equations/ideas
n1*sin(theta1)=n2*sin(theta2)

Trying to solve
I know I must use triangles to figure out the angles needed for Snells law, but have more unknown variables than equations to relate them so I don't know how to solve for them
 
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Have you come across real and apparent depth? For example, when you look into a pool of water, it appears shallower than it really is, due to refraction.

Also, you could pick an arbitrary angle and do the calculation for that. Edit: And I'd always start with a diagram (or several.)
 
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