# Induced EMF in Non-Uniform Magnetic Field

## Homework Statement

A square wire loop of dimensions L X L (L = 15.5 cm) oriented in the xy-plane and centered on the x-axis enters a region where the magnetic field (B = 0.855 T) is first oriented in the +z- and then in the -z-direction as shown in the diagram below. (Note: W = 15.501 cm and the magnetic field is zero outside the shaded area.) The loop moves at speed v = 4.55 ms in the +x-direction. In the questions that follow, when asked for the emf, a positive emf will be defined as an emf induced counterclockwise (if viewed from above the loop); and vice versa.

(i.) What is the induced emf in the loop when the center of the loop is at x = -W?
(ii.) What is the induced emf in the loop when the center of the loop is at the origin?
(iii.) What is the induced emf in the loop when the center of the loop is at x = +W/2?
(iv.) What is the induced emf in the loop when the center of the loop is at x = +W?

See below

## The Attempt at a Solution

I think if I get help on one of them, then I should be able to figure out the others.
I'm not too sure how to approach this one, but I was thinking to use E=Blv or the flux=BA equation. But I'm not sure how that works out

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no one can help me with this ? =/

still looking for help ...

In general emf = vBL for these sorts of situations but a drawing would be nice.

As WatermelonPig said, EMF=vBl
and its polatiry can be found out by F=q vXB (cross product)

bt we need a diagram to understand the question

Oh, sorry, wasnt paying attention that I didn't have one attached!

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(i) when center will be at x=-w ... which part of loop will be inside mag. field area and which part will induce emf (for this, you should have studied motional emf)

only half of the loop will be inside the magnetic field that is pointing up. the left side half isn't in a B field. So just the right side that's in the magnetic field induces emf?

yes, thats correct :)

so, what does that mean haha i still am not sure what to do for it

you did first
now for second, you need to find polarity of induced emf in on the 2 wires (left and right) of loop ...

for this use the formula of force on moving charge in mag. field, $\vec{F} \ = \ q \ \vec{v} \times \vec{B}$

As you would know, the wire moving in mag. field will act like a battery with a (+) and a (-) pole.
suppose there is a positive charge in wire moving with wire ... find direction force on it (generally along wire in these kind of questions). the side where + charge moves is (+) and other is (-)

thus find net emf in wire in case (ii)

so wait .. i dont get it, how did i do the first one?

and for (ii.) how do you use that without q ?

Last edited:
vela
Staff Emeritus
Homework Helper
Since you're dealing with a loop, it would be more straightforward to calculate the rate of change of the magnetic flux through the loop to find the emf.

motional EMF in a wire moving in mag field is vBL , here v is velocity B is mag field and L is the length.

motional EMF in a wire moving in mag field is vBL , here v is velocity B is mag field and L is the length.
i did that already it was wrong

is it sign problem or magnitude is wrong?

Oh wait, I got it now :)
Okay, for the second: i dont get what youre saying for that ..

Can I please have some help on the other one's then?

do you know how to find polarity of the charges in a wire?

i dont think ... im not too sure what that means

i dont think ... im not too sure what that means
When a wire will move in mag. field, EMF will be induced in it.

so there will be a current flowing in wire and thus one end will get positive charge and other negative.

Can you find which end will get which charge?

.. i have no idea?

you know of formula for force on a charge in magnetic field ... F = q (v X B)

lets suppose there is a positive q charge inside the wire ... This charge will feel a mag. force when wire is moving ... find the direction of this force ... q will move in direction of Force and the side of wire where it moves will get (+) and other (-)

wouldnt the force just be in the direction opposite of the motion, so. then the left side would be positive and the right side would be negative

is that right?