Induced EMF within a part of a parallel circuit?

[meBigGuy]

WOW. I'm so confused about what is so confusing. Assume 3 legs with 100 ohms. Then assume a 5V EMF supply in one leg. It will have no effect on the other two legs because there is a 20V supply that keeps the voltage at a constant across all three legs. The current from the main supply will vary, but the voltage will be constant. If you add a 4th resistor in series with the 20V supply (and all three legs), THEN you will have interactions.

You need to draw a schematic with 4 resistors, 3 resistive legs, and 2 supplies. Then you have something to analyze.

 

[jim hardy]

You need to draw a schematic with 4 resistors, 3 resistive legs, and 2 supplies. Then you have something to analyze.

i hope i addressed the right image.

Let's analyze the last circuit drawn. I've added to it in red...
let us write KVL twice, once around outside path and again around inside path

Outside path:
-20_supply -5_induced +Vload = 0

inside path
-20_supply -0_{across wire} +Vload = 0

Rearranging,
Outside path Vload = 20_supply +5_induced
Vload = 25

Inside path Vload = 20_supply +0_{across wire}
Vload = 20

well,
there's only one Vload, so we can set the equations equal and get result 20 = 25
or
we can subtract the equations
Vload - Vload = 25 - 20
which yields 0 = 5

Kirchoff's law did not fail. It told us that analyzing an impossible circuit yields an impossible result.

MBG is right, one needs a plausible circuit to analyze.

Mr Phi just needs to become more adroit with his "idealized components".

The lumped element model of electronic circuits makes the simplifying assumption that the attributes of the circuit, resistance, capacitance, inductance, and gain, are concentrated into idealized electrical components; resistors, capacitors, and inductors, etc. joined by a network of perfectly conducting wires.

it'll come with practice. We learn from our mistakes - so make lots of 'em.

 

[meBigGuy]

I'd start by removing the short across the VS supply, or turn it into a resistor that's twice the value of the load. Then you will see what is basically going on.

 

[jim hardy]

does this help ?

An ideal wire is a superconductor.
You cannot change flux through a superconducting loop - Lenz's law says current in the loop will become whatever is necessary to keep flux constant.
Faraday tells us constant flux means no dΦ/dt, so no induced voltage.

We see that demonstrated often in levitation experiments.
www.youtube.com/watch?v=4W9HxLOvDus

 

[PhiowPhi]

Well, I have a long way to go. Can't jump things in a matter of month/weeks lol.
But I'll start playing around with circuits soon, I've added that to the list of hobbies, but as an ME undergrad I doubt I'll invest much time into them.

 

[jim hardy]

Electronics can be a lot of fun. Look into hobbyist kits. We learn by doing.