Inductance: Current in terms of Voltage

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SUMMARY

The discussion centers on calculating the voltage required to reduce the current in a 0.6H inductor from 8A to 0A over a period of 0.4 seconds. The participant initially calculated a voltage of 12V, but the correct voltage, as established through the integral equation for inductance, is -12V. This discrepancy highlights the importance of correctly applying the formula and understanding the sign convention in inductive circuits.

PREREQUISITES
  • Understanding of inductance and its role in electrical circuits
  • Familiarity with the integral form of the inductor current equation
  • Knowledge of basic circuit analysis and voltage-current relationships
  • Proficiency in handling time-dependent equations in electrical engineering
NEXT STEPS
  • Review the derivation of the inductor current equation in electrical engineering textbooks
  • Study the effects of voltage polarity in inductive circuits
  • Learn about the application of Kirchhoff's laws in analyzing RL circuits
  • Explore advanced topics in transient analysis of inductive loads
USEFUL FOR

Electrical engineering students, circuit designers, and professionals working with inductive components in power systems.

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I'm having a bit of trouble getting the right answer for a problem in my electrical engineering textbook. The question is:

At t=0, the current flowing in a 0.6H inductance is 8A. What constant voltage must be applied to reduce the current to 0A at t=0.4s.

I'm using the equation:

i(t)=\frac{1}{L}\int\ v(t).dt+i(t_{0}) with limits 0.4s and 0s

The answer I'm getting is 12V, and the book says 10V.. which is right??

I'm using L=0.6H, i(t0)=8A, and i(t)=0A

Please help!
 
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It seems the book answer is wrong. And so is yours. The correct answer would be -12V.
 

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