Inductance of DC Electromagnet Coil. Help

AI Thread Summary
The discussion centers on calculating the inductance of a DC electromagnet coil with a resistance of 490 ohms and an impedance of 523 ohms, powered by 110 volts at 0.21 amps. Participants clarify that knowing the frequency of the current is essential for accurate calculations, with a common assumption of 60Hz for AC. The formula for inductive reactance (XL = ωL) is emphasized, where ω is derived from the frequency. A calculation method is suggested, using the impedance formula Z^2 = R^2 + (ωL)^2 to solve for inductance. The importance of frequency in determining inductance is reiterated throughout the discussion.
wingsofdesire
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I am trying to make a DC electro magnet coil. The Coil is wound up to the core. And works fine. But I'm not being able to find out the inductance of the coil. The Resistance of Coil R20= 490 ohms. Impedence is 523 Ohms. 110v give .21 amps. Please Help.
 
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Is the 110v alternating or direct current? If alternating current, what is its frequency?
 
modmix said:
what about this:
Given we have just R and L (no C).
They from a triangle: Z^2 = R^2 + L^2.
=> L = sqrt(Z^2 - R^2) = 182 Ohm.

hth
Ulli

That is not correct, you need to know the frequency as has been hinted at. XL = ωL
 
You say 110volts so I would guess that f = 60Hz (or maybe 50Hz)
The impedance = 110/0.21 = 523Ω. ω Is 2∏60 = 377
So if you do 5232 = 4902 + (ωL)2...see what you get for L.
 
technician said:
That is not correct, you need to know the frequency as has been hinted at. XL = ωL
sure. that's why i deleted my posting - not fast enough...
L measures in H ,-)
 

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