Inelastic collision of a cannonball

AI Thread Summary
In an inelastic collision involving a cannonball and a tank, momentum is conserved while kinetic energy is not. The cannonball embeds into the tank upon impact, and the combined system then moves on a rough surface, where friction plays a significant role. The energy from the cannonball is partly converted into work to overcome friction, which affects the motion of the tank. The calculations show that the initial velocity of the cannonball is determined to be 377 m/s. This confirms the understanding that while momentum remains constant, kinetic energy is dissipated due to non-conservative forces like friction.
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Homework Statement


CRsm8fL.png

Homework Equations


Total initial momentum = total final momentum
Momentum = m*v
Kinetic energy = 1/2 * m * v2

The Attempt at a Solution


What I found so far:
m1v1i = (m1+m2)vf
Total kinetic energy = 1/2 * (m1 + m2)vf2 - 1/2 * m1 * v1i2

I am confused on how friction comes into play here. I know that friction is a non-conservative force.
 
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reminiscent said:

Homework Statement


CRsm8fL.png

Homework Equations


Total initial momentum = total final momentum
Momentum = m*v
Kinetic energy = 1/2 * m * v2

The Attempt at a Solution


What I found so far:
m1v1i = (m1+m2)vf
Total kinetic energy = 1/2 * (m1 + m2)vf2 - 1/2 * m1 * v1i2

I am confused on how friction comes into play here. I know that friction is a non-conservative force.
You can take the whole process as two stages.
The cannonball hits the tank, and is embedded. What kind of collision is this? Is energy conserved?
After the collision, the tank and the ball inside, move on a rough pavement and come to rest at 50 cm distance. What kind of motion is that?
 
reminiscent said:

Homework Statement


CRsm8fL.png

Homework Equations


Total initial momentum = total final momentum
Momentum = m*v
Kinetic energy = 1/2 * m * v2

The Attempt at a Solution


What I found so far:
m1v1i = (m1+m2)vf
Total kinetic energy = 1/2 * (m1 + m2)vf2 - 1/2 * m1 * v1i2

I am confused on how friction comes into play here. I know that friction is a non-conservative force.
The energy imparted to the tank by the projectile must be used to move the tank against the friction which exists between the tank and the pavement. In essence, part of the energy of the projectile must be converted to work in order to overcome friction.
 
So since this is an elastic collision, momentum is conserved but KE is not. I would have to substitute what I found first into Kf, then that would equal to mu*(total mass)*g*d, correct? I just solve for v initial for the cannon ball. I got 377 m/s.
 
reminiscent said:
So since this is an elastic inelastic collision, momentum is conserved but KE is not. I would have to substitute what I found first into Kf, then that would equal to mu*(total mass)*g*d, correct? I just solve for v initial for the cannon ball. I got 377 m/s.
The result is correct.
 
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