Inequality intersection help

  • #1
thereddevils
438
0

Homework Statement


[tex]|2x-1|+|x+2|\geq 4x[/tex]


Homework Equations





The Attempt at a Solution



For x<-2 , [tex]-(2x-1)-(x+2)\geq 4x[/tex]

[tex]x\leq -\frac{1}{7}[/tex]

For [tex]x\geq \frac{1}{2}[/tex]

[tex]2x-1+x+2\geq 4x[/tex]

[tex]x\leq 1[/tex]

For [tex]-2 \leq x < \frac{1}{2}[/tex] ,

[tex]-(2x-1)+x+2\geq 4x [/tex]

[tex]x\leq \frac{3}{5}[/tex]

after combining , the solution would be [tex]x\leq -\frac{1}{7} [/tex]

AM i correct ? but the answer given is [tex]x\leq 1[/tex]
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
25,838
255
Hi thereddevils! :wink:

Your three answers are correct, but you're not putting them together correctly.

For example, you have:

if x ≤ -2, it's true for x ≤ -1/7.

so it's true for all x ≤ -2.

ok, now try the others. :smile:
 
  • #3
thereddevils
438
0


Hi thereddevils! :wink:

Your three answers are correct, but you're not putting them together correctly.

For example, you have:

if x ≤ -2, it's true for x ≤ -1/7.

so it's true for all x ≤ -2.

ok, now try the others. :smile:

thanks tiny , yeah , i am confused with the last part , what i did is to put x<= -1/7 , x<=1 , x<= 3/5 on the number line and take the intersection which is what i got .

so say for x>= 1/2 , x can be 4 , x<=1 , so 4<=1 ?? this is not true

i am sorry , i still do not understand the last part .
 
  • #4
tiny-tim
Science Advisor
Homework Helper
25,838
255
There are three possibilities:

x ≤ -2, -2 ≤ x ≤ 1/2, 1/2 ≤ x.

call them A B and C.

So A or B or C.

If A, the equation is true if (say) a.

If B, the equation is true if (say) b.

If C, the equation is true if (say) c.

So the equation is true if (A and a) or (B and b) or (C and c). :wink:
 

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