- #1
Cosmophile
- 111
- 2
Homework Statement
[tex] \ln \frac{(x+1)}{(x-1)} \geq 0 [/tex]
Homework Equations
[tex] \ln \frac {a}{b} = \ln a - \ln b [/tex]
[tex] \ln \frac {(x+1)}{(x-1)} = \ln (x+1) - \ln (x-1) [/tex]
The Attempt at a Solution
[tex] \ln (x+1) \geq \ln (x-1) [/tex]
[tex] e^{\ln (x+1)} \geq e^{\ln (x-1)} [/tex]
[tex] (x+1) \geq (x-1) [/tex]
According to Wolfram, the solution is ##x > 1##, but my skills with logs and exponentials are clearly very rusty.