Infinite Curvature: Understanding Black Holes

pibomb
Messages
60
Reaction score
0
What does it mean for something to have an infinite curvature (like a black hole?)?
 
Physics news on Phys.org
Black holes do not necessarily have to have infinite curvature, but enough mass to prevent light from escaping its gravitational pull. Infinite curvature would require an infinitely massive object; it's only a theoretical idea and is probably not possible. Einstein didn't believe that space time could rip, but only bend.

If it could exist, it would mean that the space-time continuum was bent to infinity. In case you don't know, the space time continuum can be thought of as a soft surface (such as a mattress), that curves when a mass is on it, and that gives us the impression of gravitational acceleration. It’s a pretty “sketchy” way of thinking about it, but it works.
 
I checked for the definition of curvature, thinking I could come up with a good answer. I found many definitions of curvature! So I am leaving this one alone
 
In GR, curvature referes to one of several "curvatuare tensors". The most fundamental of these is the Riemann curvature tensor - if you know the values of the components of the Riemann curvature tensor, you can calculate the values of the other tensors (most notably the Ricci, Einstein, and perhaps the Weyl).

A tensor is not just a single number, but an "array" of related numbers.

"Infinite" means that the value of at least one of the components of said tensor (remember, a tensor is not just a single number) increases without bound as one approaches a point, such as the singularity of a black hole. This is usually taken to imply that the theory itself breaks down and is not valid at that singular point.

Unfortunatly, there isn't any really super-simple way to describe what the Riemann curvature measures, though this is discussed in, for instance:

http://math.ucr.edu/home/baez/gr/outline2.html
http://math.ucr.edu/home/baez/einstein/node9.html
 
Last edited:
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...

Similar threads

Replies
14
Views
2K
Replies
4
Views
2K
Replies
22
Views
3K
Replies
20
Views
2K
Replies
40
Views
3K
Replies
46
Views
7K
Replies
43
Views
3K
Replies
19
Views
282
Back
Top