Infinitesimal, Snell's law, and ray tracing

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SUMMARY

This discussion focuses on the analytical calculation of the derivative d(alpha1)/d(v1) in the context of Snell's law, specifically when light transitions between two fluids with different velocities, v1 and v2. The relationship defined by Snell's law, v1/v2 = sin(alpha1)/sin(alpha2), is central to the inquiry. Participants emphasize the importance of using a diagram to visualize the relationship between angles alpha1 and alpha2, which aids in deriving the necessary expressions. Ultimately, the user successfully resolves their query by employing a diagram to clarify the relationships involved.

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ytht100
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With FIXED SOURCE AND RECEIVER, I have a light incident from fluid 1 with velocity v1 into fluid 2 with velocity v2. Obviously, according to Snell's law, v1/v2=sin(alpha1)/sin(alpha2), where alpha1 and alpha2 are the angles with regard to the vertical line.

My question is: how to calculate d(alpha1)/d(v1)?

Obviously, I can obtain the result from numerical calculation, but I am seeking analytical method. I guess maybe I need some approximation to calculate that?

Please note v2 is always constant, please also note when v1 changes, alpha1 and alpha2 change. Please note direct differentiation of Snell's law, I can obtain d(alpha1)/d(alpha2). I am clueless and have already tried several methods but obtain no result, please help!
 
Last edited:
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Have you drawn a diagram? If you do so, you ought to be able to see a relationship between ##\alpha_1## and ##\alpha_2##.
 
Thank you very much for your kind answer. Yes, I have drawn it. I am NOT seeking a relationship between alpha1 and alpha2. I am seeking relationship between d(alpha1) and d(v1), in which d represents differentiation.
 
And you can get that by using a relationship between ##\alpha_1## and ##\alpha_2## to eliminate ##\alpha_2## from your Snell's Law expression.
 
Last edited:
Ibix said:
And you can get that by using a relationship between ##\alpha_1## and ##\alpha_2## to eliminate ##\alpha_2## from your Snell's Law expression.

Sorry you answer is NOT clear. I have tried everything that I can think of for several days, can you write down specific equations? Thank you very much!
 
I can help you find the answer, but I can't give it to you. The aim of this site is to help you learn, not to do things for you.

You say the source and receiver are fixed. Where are they? Write down the coordinates. Then, work out where the ray traveling from source to receiver crosses from one medium into the other (this is where a diagram will help you). That will give you a second expression relating ##\alpha_1## and ##\alpha_2##.
 
ytht100 said:
Thank you very much for your kind answer. Yes, I have drawn it.

show us your diag. so we can confirm you are on the right path
 
Thank you all for your kind answer. I have figured it out by using the diagram. Kind regards!
 

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