Initial Velocity: Stone Released from Balloon

Click For Summary

Discussion Overview

The discussion revolves around the initial velocity of a stone released from a balloon that is moving upwards with a constant velocity. Participants explore the implications of the stone's initial velocity at the moment of release and the differences compared to a stationary balloon scenario.

Discussion Character

  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • Some participants propose that the initial velocity of the stone is equal to the velocity of the balloon but with opposite sign, questioning how this is possible.
  • Others argue that the initial velocity of the stone should have the same sign as the balloon's velocity, suggesting a misunderstanding in the initial claim.
  • A participant challenges the idea that the stone would have zero velocity at the moment of release, drawing a parallel to the act of throwing an object upwards from a moving hand.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between the stone's initial velocity and the balloon's velocity, indicating that multiple competing interpretations remain unresolved.

Contextual Notes

There are unresolved assumptions regarding the definitions of velocity at the moment of release and the conditions under which the stone is released from the balloon.

manimaran1605
Messages
60
Reaction score
0
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how? What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).
 
Physics news on Phys.org
manimaran1605 said:
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how? What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).

So you're saying that there's NO difference between just releasing the stone from a stationary balloon that isn't moving? Think again.

Zz.
 
  • Like
Likes   Reactions: 1 person
manimaran1605 said:
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how?
No, not opposite sign. Same sign.
What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).
You're free to think whatever you want. That doesn't make it right.
 
manimaran1605 said:
What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).

Think about that for a moment. When you throw a stone upwards, you release it from your hand while your hand is moving upwards rapidly... What happens?
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 60 ·
3
Replies
60
Views
6K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
12
Views
4K
  • · Replies 4 ·
Replies
4
Views
1K