Inputting tan-1(-5/2) on a Calculator

  • Thread starter Thread starter dankelly08
  • Start date Start date
dankelly08
Messages
15
Reaction score
0
how do you type in,

tan-1(-5/2) (or any negative number)

on the calculator?? or just work it out?
 
Mathematics news on Phys.org
Are you talking about the (-5/2)? Most calculators have a separate key for that, which usually has something like "(-)" printed on it (a short dash in parentheses), rather than the normal (longer) minus sign "{}-{}".

If you are referring to the -1: there should again be a separate key. On my TI calculator it is Second + Tan, just find where is says tan-1, atan, arctan, or something like that. Note that you should consider "tan-1" as a single function, it's not something like x-1 = 1/x, for which you can write in general x-n = 1/xn. Instead, it is defined by tan-1(tan(x)) = x.
 
Yeah I got it, thanks alot! it was(+/-)

I spent a full hour trying to figure that out lol..:redface:
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top