Instantaneous Velocity Car Problem

AI Thread Summary
To calculate the average velocity of a car described by the equation x(t) = bt^2 - ct^3 over the interval from t=0 to t=10, divide the total distance traveled by the time taken. The discussion highlights the confusion between average and instantaneous velocity, clarifying that the latter requires taking the derivative of the displacement function. To determine when the car is at rest again, one must find when the velocity, derived from the displacement equation, equals zero. The quadratic formula can be used to solve for the time variable t. This problem illustrates the importance of understanding the difference between average and instantaneous velocity in physics.
mopar969
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A car is stopped at a traffic light. It then travels along a straight road so that its distance from the light is given by x(t)= bt^2 -ct^3, where b = 2.40m/s^2 and c = 0.120 m/s^3. How do you calculate the average velocity of the car for the time interval t=0 to t=10.

I think that maybe I need to take the derivative of the equation but then what please help!
 
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Hello mopar969,
mopar969 said:
How do you calculate the average velocity of the car for the time interval t=0 to t=10.
If you only need to find the average velocity, simply calculate the total distance traveled, divided by the time it takes to get there.
 
Thank you. I can't believe that it was that simple. I was thinking instantaneous velocity that is why I was thinking about taking its derivative.
However, the question has another part to it that I am stuck on it says:

How long after stating from rest is the car again at rest? Please Help and Thanks.
 
You're searching the time t when the velocity is 0.

x(t)= bt^2 -ct^3, this finds the displacement as a function of time. You'll need another equation (related to this one) to find the velocity as a function of time.
 
Would I need the derivative of the displacement function?
 
Yes that would give you the velocity.
 
My next problem is how do I get t by itself?
 
Never mind I realized that I could use the quadratic formula.
 
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