Instantaneous velocity expression

[UrbanXrisis]

This is an equation of a position v time graph:

x=342t^4-127t^3+1.87t^2+2.45t

I need to use this expression to find the instantaneous velocity at t=0.000s

 

[arildno]

And how is inst. velocity related to position?

 

[Tom McCurdy]

take the derivative of the first equation
then just plug in t
and volla you got instantious velocity

 

[UrbanXrisis]

x`=1368t^3-381t^2+3.74t+2.45

is that correct?

 

[Tom McCurdy]

When you are done check your answer

This is what i got
its in white so you must highlight
1368x^3 - 381x^2+3.74X+2.45
=2.45=instant velocity

lol
oh t is 0
well this is how you would find instant acceleration at other times
4104x^2-762x+3.74

sorry I added extra but I am just learning this so I thought it would be good practice.

 

[Tom McCurdy]

Oh sorry I guess tex equations don't turn white

 

[arildno]

Besides, you used x as the variable rather than t

 

[Tom McCurdy]

Darn I was so close to getting it right