Integral for a differential equation problem

sihag
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i'm stuck on this relatively simply integral for a differential equation problem ...

| du / cos(pi/4 - u )
where | denotes the integral sign

some help ?
 
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sihag said:
∫ du / cos(π/4 - u)

Hi sihag! :smile:

Hint: substitute v = u - π/4. :smile:

(and copy the symbols below for future use! :smile:)
 
After letting \frac{\pi}{4} - u =x, all you need to know is \int \frac{1}{\cos x} dx = \log_e | \frac{1+\sin x}{\cos x} | + C.
 

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