MHB Integral: Investigating Convergence I

maxkor
Messages
79
Reaction score
0
Investigate the convergence of the integral
$\int_{0}^{\infty} \frac{-\ln \left[ \frac{1}{a} x ^{ \frac{2}{a-1} } e ^{- x^{\frac{2}{a} }} \right] }{1+x^2} \mbox{d}x$ for $a \ge 2$
 
Physics news on Phys.org
maxkor said:
Investigate the convergence of the integral
$\int_{0}^{\infty} \frac{-\ln \left[ \frac{1}{a} x ^{ \frac{2}{a-1} } e ^{- x^{\frac{2}{a} }} \right] }{1+x^2} \mbox{d}x$ for $a \ge 2$

If You write the integral as ...

$\displaystyle I = \int_{0}^{\infty} f(x)\ d x = \int_{0}^{\infty} \frac{\ln a - \frac{2}{a-1}\ \ln x + x^{\frac{2}{a}}}{1 + x^{2}}\ dx\ (1)$

... in x tends to $\infty$ You have $\displaystyle f(x) \sim \frac{x^{\frac{2}{a}}}{1 + x^{2}}$, so that the integral converges for a>2 and diverges for a=2...

Kind regards

$\chi$ $\sigma$
 
Last edited:
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 17 ·
Replies
17
Views
1K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K