- #1
The dirac delta function has the great property that ##\int_{-\infty}^{\infty} \delta(x) dx = 1 ##.
Couple that with what you know about when it is not equal to zero, and these integrals are quick and easy.
In the future, please put a little more meat into you post, so we can better understand what you already know and what you need help fixing.
The second one would be 0 since -0.5 is not in the interval of integration .Using the rule you attached, you should get 1 in the first integral. What about the second?
It is a Chegg solution . And it confused me .Where did you get that image? That is not how the Dirac Delta is defined...
I think the proof is the rule you quoted in post 3. The Chegg solution appears to be for a unit step function, not for a delta function. It's wrong.It is a Chegg solution . And it confused me .
I believe that the first integral should be 1 , i just need more proof
No worries . I showed my efforts in attached file@Legend101, if you start another thread with no effort shown, it will be deleted.
You need to show what you have tried in the first post of the thread. And it would be better to include the work directly in the post, rather than an image of the work.No worries . I showed my efforts in attached file
The work involves many integrals and mathematical notations . It would be hard to show all the work directly written on the post especially if someone is using a smartphone .You need to show what you have tried in the first post of the thread. And it would be better to include the work directly in the post, rather than an image of the work.
See my post in that thread.The work involves many integrals and mathematical notations . It would be hard to show all the work directly written on the post especially if someone is using a smartphone .