Integral of 1/sqrt(x)exp(-ix) dx

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SUMMARY

The integral of 1/sqrt(x)exp(-ix) dx from negative infinity to infinity presents challenges primarily due to the limits of integration and the nature of the function. Substituting x with u^2 complicates the limits, leading to imaginary infinities. Jordan's Lemma is not applicable here since 1/sqrt(x) lacks residues. The discussion emphasizes the need to split the integral into two parts and correctly handle the limits for both positive and negative x.

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VVS
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Hi,

I am just doing this out of curiousity.

Homework Statement



I want to integrate 1/sqrt(x)exp(ix) dx from minus infinity to infinity.


Homework Equations





The Attempt at a Solution



I had a couple of ideas one was to substitute x=u^2
but then you mess up the limits and you get minus imaginary infinity.

The other idea was to use Jordan's Lemma. But as far as I know 1/sqrt(x) doesn't have a residue so it can't be applied.

How do you solve this integral then?

thank you
 
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That substitution looks like a good idea, if you split up your integral into two parts first.
 
Hey,

Thanks for the hint. I have done the splitting, but I am not sure about the limits.

If I set u=sqrt(x) then the lower limit is plus or minus imaginary infinity and moreover the upper limit can take two values: plus infinity or minus infinity.

I don't know how to integrate that. I am aware that cos(x^2)dx and sin(x^2)dx are the well known fresnel integrals.

thanks for your help.
 
For x from 0 to plus (real) infinity, u goes from 0 to plus (real) infinity.
For negative x, you can transform the integral to the integral for positive x.
 

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