The discussion revolves around the integral of the function (1-x)/x^2, with participants questioning the correctness of a proposed solution involving logarithmic terms.
The conversation is ongoing, with multiple interpretations of the integral being explored. Some participants have provided insights into the potential discrepancies in the answers generated by Mathematica, particularly regarding the use of logarithmic bases.
There appears to be confusion regarding the representation of logarithmic functions and the implications of different bases, as well as the correctness of the integral's evaluation.
+ln(x) should be -ln(x)m1ndpixel said:Hi,
The integral of ((1-x)/x^2)dx is: -(1/x) + ln(x) + c
Is that correct?
Mathematica is giving some strange answer containing a log.
Thanks
m1ndpixel said:sorry, yes that's what i meant!
Almost. (1-x)/x2= 1/x2- 1/x and the integral of that is -1/x- ln(x)+ cm1ndpixel said:Hi,
The integral of ((1-x)/x^2)dx is: -(1/x) + ln(x) + c
Is that correct?
??YOUR answer contains a log! What was the strange answer Mathematica gave? If you mean that Mathematica is giving an answer with a logarithm base 10, perhaps it is using the fact that ln(x)= log(x)/log(e) where "log" is logarithm base 10. If it is just giving -1/x- log(x)+ c, then it is using "log" to mean natural logarithm. That is fairly standard now where common logarithms are not much used.Mathematica is giving some strange answer containing a log.
Thanks