Integral of a continuously differentiable function on [a,b].

rsa58
Messages
83
Reaction score
0
suppose f is real, continuously differentiable function on [a,b], f(a)=f(b)=0 and

integral f^2dx=1

show [integral(xf(x)f'(x)dx)= -1/2 over [a,b]
 
Last edited:
Physics news on Phys.org
How can you write the term f(x)\,f'(x)?
 
rsa58 said:
suppose f is real, continuously differentiable function on [a,b], f(a)=f(b)=0 and

integral f^2dx=1

show [integral(xf(x)f'(x)dx)= -1/2 over [a,b]
Integrate by parts:

You will get 1/2(bf2(b)-af2(a)-integral(a,b)f2(x))
 
Elaborating on Rainbow Child's suggestion, what is the derivative of (f(x))2?
 

Similar threads

Replies
6
Views
1K
Replies
6
Views
3K
Replies
12
Views
2K
Replies
20
Views
4K
Replies
1
Views
1K
Back
Top