Integral of E dot dA - conceptual

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Homework Help Overview

The discussion revolves around the integral of the electric field vector E and the differential area vector dA, specifically in the context of electric flux. Participants are trying to understand the relationship between the given area vector A and the differential area vector dA, and whether the problem is rooted in multivariate calculus concepts.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants express confusion about how to relate the area vector A to the differential area vector dA, questioning whether derivatives are involved. Others seek clarification on the physical meaning of dA and its relation to the surface over which the integral is performed.

Discussion Status

The discussion is ongoing, with participants exploring the definitions and roles of the vectors involved. Some guidance has been offered regarding the interpretation of dA as a vector normal to a surface, but there is still uncertainty about the surface itself and the clarity of the problem statement.

Contextual Notes

Participants note that the problem lacks a specified surface for integration, which complicates the understanding of the integral. There is also mention of the answer being given as 8 flux units, raising questions about the mathematical validity of the approach taken.

quantum13
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Homework Statement


A = 2i + 3j
E = 4i

determine the integral of E dot dA

Homework Equations


Integral calculus, vectors

The Attempt at a Solution


I don't understand why one could do this. The integral is of E and dA, not E and A. How can I use A to determine dA? Do I take its derivative? Then I would only get dA = 0.Also: This is part of an electric flux problem. Is this a basic of multivariate calculus? I'm indecisive on whether or not I should get a MV calc textbook - I don't have one yet, but I don't want basic questions like this holding me back either. I'm studying from Halliday's Fundamentals of Physics which apparently isn't a calculus heavy text.
 
Last edited:
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the question isn't very celar, but here's my 2 cents...

E is the electric field vector

Generally A represent some surface or area A. dA is vector in the direction normal to surface. If n is a unit vector in that direction, dA is a scalar infintesimal area, then

\texbf{dA} = \textbf{n}dA
with
A = \int dA

For a vector field E, the flux is given by
\Phi = \int \textbf{E} \bullet \textbf{dA}

physically the dot product means if the vector is parallel to the surface its contribution is zero, or maximum when it is perpindiuclar to the surface (passing through it). The integral just sums all the contributions across the whole surface.

so is there anymore to make the question clearer?
what area do you integrate over?
A is given as a vector - does this represent a normal to a plane or something?
 
quantum13 said:

Homework Statement


A = 2i + 3j
E = 4i

determine the integral of E dot dA

Homework Equations


Integral calculus, vectors


The Attempt at a Solution


I don't understand why one could do this. The integral is of E and dA, not E and A. How can I use A to determine dA? Do I take its derivative? Then I would only get dA = 0.


Also: This is part of an electric flux problem. Is this a basic of multivariate calculus? I'm indecisive on whether or not I should get a MV calc textbook - I don't have one yet, but I don't want basic questions like this holding me back either. I'm studying from Halliday's Fundamentals of Physics which apparently isn't a calculus heavy text.
You are right. The problem as stated makes no sense. I suggest you go back and reread the problem. It may be that you have overlooked something. "dA" should be a "vector differential of area" of some surface, not just a vector. Are you not given a surface to integrate over?
 
I'm sorry. dA is in fact an area vector perpendicular to a surface. However, the surface is definitely not stated. The answer is given as 8 (flux units). Does it make any mathematical sense to do this?

\Phi = \int \vec{E} \cdot \vec{dA}

<br /> \Phi = \vec{E} \cdot \int \vec{dA} <br />

<br /> \Phi = \vec{E} \cdot \vec{A} <br />Then
Phi = (4i) dot (2i + 3j)
= 8

No clue if this makes any sense or not but...?
 
Last edited:

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