Integral of f(z) dz Around C1 & C2: Complex Math Solutions

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The discussion revolves around calculating the integrals of the function f(z) = z²/sin²(z) around two specified contours, C1 (|z| = 1) and C2 (|z - π| = 1). The Cauchy Integral formula and residue theorem are considered for solving these integrals. It is noted that f(z) has a removable singularity at z = 0, making it analytic there. The integral around C1 is calculated to be 2πi, while the integral around C2 is determined to be 4π²i. The conversation highlights the importance of understanding singularities and residues in complex analysis.
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Homework Statement


We know sin(z) has zeros at integral multiples of pi. Let f(z) = z2/sin2(z)
How do I find the integral of f(z) dz around C1 (C1 is the circle |z| = 1 orientated anti-clockwise) and how do I find the integral of f(z) dz around C2 (C2 is the circle |z - pi| = 1 orientated anti-clockwise).

Homework Equations





The Attempt at a Solution


Do I use the Cauchy Integral formula for these integrals.
If not, how would I go about doing these.
 
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how about thinking residues?
 
I got 1 as my integral.
 
No. 1 is my value of f(z) (using L'Hopitals rule and the fact that f(z) has a removable singularity at z = 0 so this function is analytic).
My limits of integration are 0 and 2pi so my integral is 2pi.
 
No again. We use the residue theorem
integral = 2 pi i (sum of the residues)
= 2 pi i (1)
= 2 pi i
and for the next integral I got 4 pi^2 i
 
Last edited:
If your function is analytic how can it have a residue at 0?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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