Integral of sin(lnx) + (lnx)^3/2 w.r.t. x

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SUMMARY

The discussion focuses on finding the derivative of the integral function g(x) defined as g(x) = ∫(0 to lnx) (sin(t) + t^(3/2)) dt. The derivative is computed using the chain rule and the fundamental theorem of calculus, resulting in g'(x) = sin(lnx) * (1/x) + (lnx)^(3/2) * (1/x). Participants emphasize the importance of understanding the fundamental theorem of calculus, particularly its second part, for solving such problems.

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  • Understanding of integral calculus
  • Familiarity with the fundamental theorem of calculus
  • Knowledge of differentiation techniques, particularly the chain rule
  • Basic understanding of logarithmic functions
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  • Study the fundamental theorem of calculus, part 2
  • Practice differentiation of integral functions
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Students and educators in mathematics, particularly those studying calculus and integral functions, as well as anyone looking to deepen their understanding of the fundamental theorem of calculus.

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g(x) = integral 0 to lnx (sin(t)+t^3/2))dt

find d/dx g(x):

let u = lnx


= sin(u) + u^3/2 du/dx
= sin(lnx)(1/x) + x^3/2(1/x)

Thanks
 
Last edited:
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What is your question?
 
I believe what you need to examine is the fundamental theorem of calculus, part 2. Check your text.

edit: in that section, you'll probably see some examples where they find the derivative of the integral of some function...
 
Last edited:

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