# Integral to find the volume of a torus

togame

## Homework Statement

Find the volume of the torus formed when the circle of radius 2 centered at (3,0) is revolved about the y-axis. Use geometry to evaluate the integral.

## Homework Equations

Formula for the semi-circle: $y=\sqrt{4-x^2}$
Solving for x give $x=\pm\sqrt{4-y^2}$

## The Attempt at a Solution

I was thinking of solving the integral from -2 to 2 using both the positive and negative sides, then evaluate the integral and then multiply by 2, but I'm not so sure about my equation.

$$2\int_{-2}^2\pi\big( (3-\sqrt{4-y^2})^2 - (3+\sqrt{4-y^2})^2 \big) \mathrm d y$$

I just seem lost on this one :(

janhaa

## Homework Statement

Find the volume of the torus formed when the circle of radius 2 centered at (3,0) is revolved about the y-axis. Use geometry to evaluate the integral.

## Homework Equations

Formula for the semi-circle: $y=\sqrt{4-x^2}$
Solving for x give $x=\pm\sqrt{4-y^2}$

## The Attempt at a Solution

I was thinking of solving the integral from -2 to 2 using both the positive and negative sides, then evaluate the integral and then multiply by 2, but I'm not so sure about my equation.
$$2\int_{-2}^2\pi\big( (3-\sqrt{4-y^2})^2 - (3+\sqrt{4-y^2})^2 \big) \mathrm d y$$
I just seem lost on this one :(
I believe the equation is:

$$V=\int_{-2}^2\pi\big( (3+\sqrt{4-y^2})^2 - (3-\sqrt{4-y^2})^2 \big) \mathrm d y$$

$$V=\int_{-2}^2\pi\cdot 12(\sqrt{4-y^2}) \mathrm d y$$

then trigonometric substitution...

Homework Helper

## Homework Statement

Find the volume of the torus formed when the circle of radius 2 centered at (3,0) is revolved about the y-axis. Use geometry to evaluate the integral.

## Homework Equations

Formula for the semi-circle: $y=\sqrt{4-x^2}$
Solving for x give $x=\pm\sqrt{4-y^2}$

## The Attempt at a Solution

I was thinking of solving the integral from -2 to 2 using both the positive and negative sides, then evaluate the integral and then multiply by 2, but I'm not so sure about my equation.

$$2\int_{-2}^2\pi\big( (3-\sqrt{4-y^2})^2 - (3+\sqrt{4-y^2})^2 \big) \mathrm d y$$

I just seem lost on this one :(

Edit : Got beat to it.