Integrals of Complex Functions

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SUMMARY

The integral of complex functions can be evaluated using the Cauchy Integral Formula and Cauchy Integral Theorem, particularly for functions such as f(z) = e^{-i5z}/(z^2 + 1) and f(z) = 1/(π)(a/(z^2 + a^2)). The discussion emphasizes the importance of integrating around the boundary of a disk, where the values inside the disk equal those on the boundary. The approach involves computing integrals on closed paths, which results in zero work done, as stated by the Cauchy Integral Theorem. Understanding these concepts is crucial for solving the given integrals in the context of Mathematical Methods of Physics.

PREREQUISITES
  • Cauchy Integral Formula
  • Cauchy Integral Theorem
  • Complex analysis fundamentals
  • Mathematical Methods of Physics knowledge
NEXT STEPS
  • Study the Cauchy Integral Formula in detail
  • Learn about the implications of the Cauchy Integral Theorem
  • Explore the relationship between complex integrals and Stokes' Theorem
  • Practice computing integrals on closed paths, specifically on the unit circle
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Students in independent study courses of Mathematical Methods of Physics, complex analysis learners, and anyone seeking to deepen their understanding of integrals of complex functions.

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Homework Statement


What is the integral from negative infinity to positive infinity of the following functions?

a) f(z) = \frac{e^{-i5z}}{z^{2}+1}

b) f(z) = \frac{e^{-i5z}}{z^{2}-1}

c) f(z) = \frac{1}{π}\frac{a}{z^{2}+a^{2}}

d) f(z) = e^{\frac{-(z-ia)^{2}}{2}}

e) f(z) = \frac{sinz}{z}

Homework Equations



All my professor showed was an example, which would be (c) above

\frac{1}{π}\int\frac{a}{z^{2}+a^{2}}dz
\frac{1}{π}\int\frac{1}{2ai}(\frac{1}{z-ia}-\frac{1}{z+ia})dz
\frac{1}{2iπ}\int\frac{1}{z-ia}-\frac{1}{z+ia} dz=1
dz\RightarrowRe^{iθ}idθ

limits of integration are now from 0 to π
\int\frac{1}{R^{2}e^{2iθ}+a^{2}}Re^{iθ}iθdθ
R^{2}\rightarrow∞
\ointf(z)dz=0
f(z) is analytic
f(z) = \frac{1}{2πi}

and this is where the class time expired and he said "you can figure out the rest"

The Attempt at a Solution


I have no clue where to start with these. The class is Mathematical Methods of Physics and this year there weren't enough students in the class so they offered it as an independent study. The professor that "observes" our work didn't tell us how to do these or where to start. I'm just looking for guidance on what to do, that an idiot can understand. Often I read threads on here and the way some of you convey your knowledge is out of my league. I would appreciate any help! Thanks
 
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So the general approach is to use the Cauchy Integral Formula and Cauchy Integral Theorem. The theorem has a wiki page, as does the formula: http://en.wikipedia.org/wiki/Cauchy's_integral_formula.

You are basically integrating about the boundary of a disk, where the values contained in the disk are equal to the values on the boundary. This should seem familiar, as it is the basis for Stokes' Theorem, and consequently Green's Theorem.

If you look at the Cauchy Integral Theorem and its proof, you can see ∫f(z)dz = 0. This is to say that for any closed path, no work is done.

My suggestion would be to compute ∫(1/z) dz on the unit circle, draw a graph of this (it will be a circle of radius 1 with a hole at R = 0), and examine its physical significance. From here, compare with the Cauchy Integral Formula and Theorem, and understand why this works.

Your reasoning behind factoring these denominators into a form of 1/(z-a) is necessary because it is just a translation of the solution to ∫(1/z) dz.
 

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