How to Integrate 1/(1+2x+x^2) dx Without Getting Stumped

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To integrate 1/(1+2x+x^2) dx, the expression can be simplified by completing the square, leading to the form 1/((x+1)^2). Substituting u = x + 1 allows for the integral to be rewritten as ∫ u^(-2) du. This substitution simplifies the integration process, making it easier to apply the power rule. The final result can be derived from this approach, providing a clearer path to the solution.
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In an exam i stumbled when i saw this q
integrate:
1/(1+2x+x^2) dx

help
 
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\int \frac{dx}{1+2x+x^2}

\int \frac{dx}{(1+x)^2}

Whats the pro
 
himanshu121 said:
\int \frac{dx}{1+2x+x^2}

\int \frac{dx}{(1+x)^2}

Whats the pro
?
?
 
1 + x^2 + \frac{1}{3}x^3
 
Last edited:
Substitute u=x+1. du=dx so we get

\int\frac{dx}{(1+x)^2}=\int\frac{du}{u^2}=\int u^{-2}du

That should make it a little easier to see what rule you can apply.
 
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