Integrate f(x) = (x^3 + 3x + 12) / (x(x+2)^2)

  • Thread starter Thread starter Hevonen
  • Start date Start date
  • Tags Tags
    Integrate
Click For Summary
SUMMARY

The integration of the function f(x) = (x^3 + 3x + 12) / (x(x+2)^2) requires the application of partial fraction decomposition. The polynomial should first be rewritten using long division to ensure the degree of the numerator is less than that of the denominator. The expression can be decomposed into the form f(x) = A/x + B/(x+2) + C/(x+2)^2, where A, B, and C are constants that can be determined by solving a system of equations. This method is essential for correctly integrating rational functions.

PREREQUISITES
  • Understanding of polynomial long division
  • Knowledge of partial fraction decomposition
  • Ability to solve systems of equations
  • Familiarity with integration techniques for rational functions
NEXT STEPS
  • Study polynomial long division techniques
  • Learn about partial fraction decomposition in detail
  • Practice solving systems of equations for constants in partial fractions
  • Explore integration techniques for rational functions in calculus
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, as well as educators seeking to reinforce concepts of polynomial division and partial fractions.

Hevonen
Messages
54
Reaction score
0

Homework Statement



Integrate f(x) = (x^3 + 3x + 12) / (x(x+2)^2)

Homework Equations




The Attempt at a Solution



I know that i should somehow rewrite the polynomial but I do not know how. Please, help me.
 
Physics news on Phys.org
Hmm, I don't know if this is correct or not, but have you tried long division?
 
You should rewrite your polynomial as sum of partial fractions, hope you know how to do that. You write
f(x) = \frac{x^3 + 3x + 12} { x(x+2)^2} = \frac{A}{x}+\frac{B}{x+2}+\frac{C}{(x+2)^2}

Where A,B,C are constants. Then you have to solve a system of three equations for A,B,C. Else you look in math book or wikipedia under partial fractions.
 
Thanks! It is about partial fractions.
 
I would strongly recommend that you multiply out the denominator and divide first. "Partial fractions" only works correctly when the numerator is of lower degree than the denominator.
 

Similar threads

Replies
4
Views
3K
Replies
19
Views
3K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
8
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K