1. The problem statement, all variables and given/known data Evaluate the indefinite integral. ∫sin(27t) (sec(cos 27t))^2 dt 2. Relevant equations 3. The attempt at a solution u = cos27t du = -27sin27t dx = du / -27sin27t ∫sin(27t)*(sec(u))^2 * (du/-27sin27t) (-1/27) ∫(sec(u))^2 du (-1/27)*tan(u) = (-1/27)*tan(cos27t) + C ? I am going on with this problem the wrong way?