Integrate sin(27t) (sec(cos 27t))^2 dt

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Homework Help Overview

The discussion revolves around evaluating the indefinite integral of the function sin(27t) multiplied by (sec(cos(27t)))^2 with respect to t. The problem involves integration techniques and trigonometric identities.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts a substitution method involving u = cos(27t) and expresses concerns about the validity of their approach. Some participants question the correctness of the resulting expression and its acceptance by an online platform.

Discussion Status

The discussion is ongoing, with some participants providing feedback on the original poster's approach. There is a suggestion to evaluate a specific numerical factor, indicating an exploration of potential simplifications or corrections.

Contextual Notes

There is mention of an online platform (Webassign) not accepting the proposed answer, suggesting that there may be specific formatting or accuracy requirements in play.

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Homework Statement



Evaluate the indefinite integral.

∫sin(27t) (sec(cos 27t))^2 dt

Homework Equations


The Attempt at a Solution



u = cos27t
du = -27sin27t

dx = du / -27sin27t
∫sin(27t)*(sec(u))^2 * (du/-27sin27t)(-1/27) ∫(sec(u))^2 du

(-1/27)*tan(u)

= (-1/27)*tan(cos27t) + C ?

I am going on with this problem the wrong way?
 
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It look s fine...

ehild
 
Is it? Webassign is not accepting that answer for some reason.
 
Try to evaluate -1/27.

ehild
 

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