Integrate sin(27t) (sec(cos 27t))^2 dt

  • Thread starter neosonata
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  • #1
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Homework Statement



Evaluate the indefinite integral.

∫sin(27t) (sec(cos 27t))^2 dt

Homework Equations





The Attempt at a Solution



u = cos27t
du = -27sin27t

dx = du / -27sin27t



∫sin(27t)*(sec(u))^2 * (du/-27sin27t)


(-1/27) ∫(sec(u))^2 du

(-1/27)*tan(u)

= (-1/27)*tan(cos27t) + C ?

I am going on with this problem the wrong way?
 

Answers and Replies

  • #2
ehild
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It look s fine...

ehild
 
  • #3
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Is it? Webassign is not accepting that answer for some reason.
 
  • #4
ehild
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Try to evaluate -1/27.

ehild
 

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