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Integrate sin(27t) (sec(cos 27t))^2 dt

  1. Jan 26, 2012 #1
    1. The problem statement, all variables and given/known data

    Evaluate the indefinite integral.

    ∫sin(27t) (sec(cos 27t))^2 dt

    2. Relevant equations



    3. The attempt at a solution

    u = cos27t
    du = -27sin27t

    dx = du / -27sin27t



    ∫sin(27t)*(sec(u))^2 * (du/-27sin27t)


    (-1/27) ∫(sec(u))^2 du

    (-1/27)*tan(u)

    = (-1/27)*tan(cos27t) + C ?

    I am going on with this problem the wrong way?
     
  2. jcsd
  3. Jan 26, 2012 #2

    ehild

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    It look s fine...

    ehild
     
  4. Jan 26, 2012 #3
    Is it? Webassign is not accepting that answer for some reason.
     
  5. Jan 26, 2012 #4

    ehild

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    Gold Member

    Try to evaluate -1/27.

    ehild
     
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