- #1

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Anyone know how to integrate this?

Thanks

Thanks

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- Thread starter coverband
- Start date

- #1

- 171

- 0

Anyone know how to integrate this?

Thanks

Thanks

- #2

- 299

- 20

Yes. Start by factoring out 1/a, then make the trig substitution [tex]x = a \sec \theta[/tex]. After simplification, you will obtain an integral in terms of secant cubed, for which there is an entire http://en.wikipedia.org/wiki/Integral_of_secant_cubed" [Broken] devoted to explaining how to integrate that. Do so, back-substitute, and simplify. Or alternatively, simply look this up in your handy table of integrals, and find that the solution is:

**<< complete solution deleted by berkeman >>**

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- #3

Fredrik

Staff Emeritus

Science Advisor

Gold Member

- 10,872

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[itex]y=\sqrt{x^2-a^2}[/itex] simplifies it a bit.

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