Integrating 1/(x+x^3+2): Simplified Steps & Techniques

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Homework Help Overview

The problem involves integrating the function 1/(x+x^3+2). The original poster attempts to apply partial fraction decomposition but finds the process complicated and seeks faster methods suitable for an elementary level test.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the original poster's attempt at integration, with some suggesting to continue with the current method despite its complexity. Others propose a substitution method involving u = x - 2, but there is uncertainty about its effectiveness.

Discussion Status

The discussion is ongoing, with participants providing suggestions and exploring different approaches. There is no explicit consensus on the best method, but some guidance has been offered regarding the substitution and continuation of the original attempt.

Contextual Notes

The problem is part of a timed test with ten questions, which may influence the urgency and approach to finding a solution.

Clara Chung
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Homework Statement


integrate 1/(x+x^3+2)

Homework Equations

The Attempt at a Solution


I have tried to use partial fraction but the process is very complicated. Are there any faster methods? It is one of the ten questions in a 50 minutes elementary level test.

Here is my attempt,
∫ 1/(x^3+x+2) dx= ∫ 1/[4(x+1)] dx - ∫ (x-2)/[4(x^2-x+2)] dx
= In(x+1)/4 - ∫ (x-2)/[4((x-1/2)^2+7/4)] dx + C
Then I have to use complicated trigonometry by letting x - 1/2 = (root 7) tan(y) /2

Please tell me if there is a faster method
 
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Don't think there's a faster method. Push forward with what you have!
 
Try the substitution ##u=x-2## on the second integral.
 
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vela said:
Try the substitution ##u=x-2## on the second integral.
Please teach me how to do after letting u = x-2
∫ (x-2)/[(x^2-x+2)] dx
= ∫ (u / (u^2 + 3u + 4)) du
=?
 
Clara Chung said:
Please teach me how to do after letting u = x-2
∫ (x-2)/[(x^2-x+2)] dx
= ∫ (u / (u^2 + 3u + 4)) du
=?

What do YOU think you should do next? What have you tried so far? (I mean besides the ##x\; \text{to}\;y## transformation you already mentioned and that you said you would like to avoid.)
 
Last edited:
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Clara Chung said:
Please teach me how to do after letting u = x-2
∫ (x-2)/[(x^2-x+2)] dx
= ∫ (u / (u^2 + 3u + 4)) du
=?
I made a mistake when thinking of how to do the integral, so I don't think this substitution really helps. As Ackbach advised earlier, just carry on with your initial attempt.
 
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So so you are doing it by stages and the second stage getting something like

$$\int \dfrac {\left( x-2\right) dx}{\left[ 4\left( x-\dfrac {1}{2}\right) ^{2}+\dfrac {7}{4}\right] } $$

(I have not checked and am not sure of the placing of the 4 and brackets from your text, but the following holds in any case).

So that is a linear (first degree) function divided by a quadratic (second degree). For the next (I am afraid not the last) step - in calculus what is the relation between some first and a second degree polynomial? :oldwink:
 
Last edited:

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