Integrating Natural Logarithms: A Scientific Approach

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The integral of ln(x) is derived using integration by parts, resulting in the formula ∫ln(x)dx = xln(x) - x + C. The integration process involves setting u = x and dv/dx = 1/x, leading to the correct application of the integration by parts formula. A participant initially questioned a step in the integration but later acknowledged their mistake after clarification. The discussion highlights the importance of careful verification in mathematical procedures. The conversation concludes with participants expressing satisfaction with the resolution of the problem.
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what is the integral of lnx?
 
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Try writing it as 1*ln(x), then integrate by parts. (Should get x*ln(x)-x).
 
could you show me the entire way?
 
Sure

∫1*ln(x)dx

du/dx = 1
v = ln(x)

u = x
dv/dx = 1/x

Now, integrating by parts:

∫1*ln(x)dx = u*v - ∫u*dv/dx
= x*ln(x) - ∫dx
= x*ln(x) - x (+ C to be pedantic)
 
i got it, thanks.

edit: just one problem should this ∫u*dv/dx=∫1
 
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Originally posted by loop quantum gravity
i got it, thanks.

edit: just one problem shouldn't this be ∫u*dv/dx=∫1 ?
lonewolf i think i am wrong but i need your verification on that.
 
never mind i found my mistake.
 
Oops, sorry LQG, I wasn't ignoring you intentionally. Glad you figured it out anyway :smile:
 
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