Integrating Square Root of a Rational Function with Variable Substitution

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vee6
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How to integrate below?

$$\int \sqrt{\frac{r^{2}-x^{2}+x^{2}}{r^{2}-x^{2}}} dx$$

neither if u = r^2 - x^2 nor u = x^2 will get the result.
 
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Try u=x/r, and simplify, it should become a standard integral (solvable with formulas, or with a trigonometric substitution)
 
vee6 said:
How to integrate below?

$$\int \sqrt{\frac{r^{2}-x^{2}+x^{2}}{r^{2}-x^{2}}} dx$$

neither if u = r^2 - x^2 nor u = x^2 will get the result.
Is this really what you meant? Since [itex]-x^2+ x^2= 0[/itex] the is exactly the same as
[tex]|r|\int \frac{1}{\sqrt{r^2- x^2}}dx[/tex]

The substitution x= sin(t) would be a stadard technique for this.