Integrating with Trigonometric Substitution: Solving ∫ x √ 4 + x2 dx

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Homework Help Overview

The discussion revolves around evaluating the integral ∫ x √(4 + x²) dx using trigonometric substitution, specifically with the substitution x = 2tanθ. Participants are exploring the implications of this substitution and the necessary transformations involved in the integration process.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are discussing the correct form of the integral and the implications of using trigonometric substitution. There are questions about how to express dx in terms of dθ and whether the chosen method is appropriate for the problem.

Discussion Status

The discussion is active, with participants providing guidance on the need to change dx and questioning the effectiveness of trigonometric substitution for this integral. There is a recognition that alternative methods may be more suitable, but no consensus has been reached on the best approach.

Contextual Notes

Some participants note that the integral may be simple enough to evaluate by inspection after familiarization with similar examples, indicating a potential constraint in the method choice based on the problem's requirements.

bengaltiger14
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Homework Statement



Evaluate ∫ x √ 4 + x2 dx by using the trigonometric substitution x = 2tanθ

I am starting on the right track by subbing x=2tanθ into x like this:


=∫ 2tanθ √ 4 + 2tanθ(2)

then, do I just integrate that for the correct answer?
 
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Just to clear up, are you integrating this:

[tex]\int \frac{xdx}{\sqrt{4+x^2}}[/tex]

or this:

[tex]\int x(\sqrt{4+x^2})dx[/tex]

Either way you'll have to put [itex]dx[/itex] in terms of [itex]d\theta[/tex] and then use a trig identity to simplify the whole integral.[/itex]
 
[tex]\int x(\sqrt{4+x^2})dx[/tex]
 
Ok, well as I said before, can you write dx in terms of [itex]d\theta[/itex] and substitute for the x's? Thats probably the first step.
 
If the question requires you to do this integral by trig substitution, then, as Kurdt has said, you have forgotten to change the dx.

If the question allows you to use any method, then tig substitution is not the best method; a different substitution is better. In fact, this integral is simple enough that, after seeing a few more examples of this type, you should be able to write down the answer by inspection.
 

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