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## Homework Statement

∫(4x^3)/√(x^2+4)dx

## Homework Equations

## The Attempt at a Solution

So, I let x= 2tanθ

dx= 2sec^2θ dθ

So, √(4tan^2(θ)+4)=2secθ

∫(4x^3)/√(x^2+4)dx=∫((32tan^3(θ))/(2secθ))2sec^2(θ)dθ.

Would it go to ∫16tan^3(θ)2sec(θ)dθ

or ∫32tan^3(θ)sec(θ)dθ