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Integration by partial fractions part. 2

  1. Feb 23, 2009 #1
    1. The problem statement, all variables and given/known data
    [tex]\int\frac{e^x}{(e^x-2)(e^2x +1)}[/tex] it should be e to the power of 2x



    2. Relevant equations
    Using substitution u=e^x, and then using partial fractions



    3. The attempt at a solution
    I have done this problem two separate ways. One with substitution and then partial fractions, and the other with just partial fractions. Both times I end with different coefficient values. I'm not sure if you can use both substitution and then partial fractions...
     
  2. jcsd
  3. Feb 23, 2009 #2
    In your equation (which I can't really read) you're missing the dx! What I recommend you do is a u substitution, but make sure you change all the things related to x to u. For example, u = e^x, then du = e^x * dx so when you substitute the e^2x on top becomes e^x (since one of them is used for the du) giving you:

    (u du) / [(u-2)(u^2 + 1)]
     
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