Integration by partial fractions part. 2

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SUMMARY

The discussion focuses on solving the integral \(\int \frac{e^x}{(e^x-2)(e^{2x} +1)} \, dx\) using substitution and partial fractions. The recommended approach involves substituting \(u = e^x\), which simplifies the integral to \(\frac{u \, du}{(u-2)(u^2 + 1)}\). Participants noted discrepancies in coefficient values when applying both substitution and partial fractions, emphasizing the importance of consistent variable changes throughout the process.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with substitution methods in integration
  • Knowledge of partial fraction decomposition
  • Experience with exponential functions and their derivatives
NEXT STEPS
  • Practice solving integrals using substitution techniques
  • Study partial fraction decomposition in detail
  • Explore integration of rational functions involving exponential terms
  • Learn about the implications of variable substitution on differential equations
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, as well as educators looking for examples of substitution and partial fractions in action.

sdoyle
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Homework Statement


[tex]\int\frac{e^x}{(e^x-2)(e^2x +1)}[/tex] it should be e to the power of 2x



Homework Equations


Using substitution u=e^x, and then using partial fractions



The Attempt at a Solution


I have done this problem two separate ways. One with substitution and then partial fractions, and the other with just partial fractions. Both times I end with different coefficient values. I'm not sure if you can use both substitution and then partial fractions...
 
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In your equation (which I can't really read) you're missing the dx! What I recommend you do is a u substitution, but make sure you change all the things related to x to u. For example, u = e^x, then du = e^x * dx so when you substitute the e^2x on top becomes e^x (since one of them is used for the du) giving you:

(u du) / [(u-2)(u^2 + 1)]
 

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