Integration by parts computation

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SUMMARY

The integral I=\int^{\pi/4}_{0}cos(xt^{2})tan^{2}(t)dt requires computation of its asymptotic expansion as x approaches infinity. The integration by parts method is applied with u=cos(xt^{2}) and dv=tan^{2}(t)dt, leading to the expression I=cos(xt^{2})tan(t)-tcos(xt^{2})+\int[2xtcos(xt^{2})tan(t)-2xt^{2}cos(xt^{2})]dt. A correction is noted in the differentiation of u, where du should be -2xtsin(xt^{2})dt instead of -2xtcos(xt^{2})dt. This highlights the importance of accurate differentiation in integration by parts.

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the_kid
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Homework Statement


Consider the following integral:

I=\int^{\pi/4}_{0}cos(xt^{2})tan^{2}(t)dt

I'm trying to compute as many terms as possible of its asymptotic expansion as x\rightarrow\infty.


Homework Equations



x

The Attempt at a Solution


Let u=cos(xt^{2}). And dv=tan^{2}(t)dt.
Then du=-2xtcos(xt^{2})dt and v=\inttan^{2}(t)dt=tan(t)-t+C.

Integration by parts yields:

I=cos(xt^{2})tan(t)-tcos(xt^{2})+\int[2xtcos(xt^{2})tan(t)-2xt^{2}cos(xt^{2})]dt,
where all terms are evaluated from 0 to pi/4, obviously.

This feels wrong to me. Can anyone give me some help?
 
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hi the_kid! :smile:

(try using the X2 button just above the Reply box :wink:)
the_kid said:
Let u=cos(xt^{2}). And dv=tan^{2}(t)dt.
Then du=-2xtcos(xt^{2})dt

erm :redface:

du=-2xtsin(xt2)dt :wink:
 

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