# Integration by Parts evaluation help

Hi,
Can you tell me if I am on the right track with this problem. Thanks in advance.

## Homework Statement

Evaluate the integral using integration by parts

ln(2x + 1)dx

## The Attempt at a Solution

ln(2x + 1)dx

= ln(2x + 1) * 1dx

Let U = ln(2x + 1)

therefore du = 1/(2x+1)

dv = 1dx

therefore v = x

Using the formula: $$\int udv = uv - \int vdu$$

= \int ln(2x + 1) * 1dx = ln (2x + 1)(x) - \int (x)(1/2x + 1)

If any of this is correct, I am now stuck at this point.

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gabbagabbahey
Homework Helper
Gold Member
Let U = ln(2x + 1)

therefore du = 1/(2x+1)
Double check that differentiation

Other than that, it looks good so far. As a hint on how to continue, [itex]\frac{2x}{2x+1}=1-\frac{1}{2x+1}[/tex]